Question

Volume strength of $1\text{M}$ solution of $H_2{O}_2$ is:

• A. $11.2$
• B. $22.4$
• C. $10.8$
• D. $21.6$

Answer 1

The correct option is A $11.2$

The balanced reaction is as follows:

$2H_2{O}_2\to 2H_{2}O+O_2$

$-1$ $-2$ $0$ (oxidation state of $O$)

So, $2$ moles of $H_2{O}_2$ gives $1$ mole of $O_2$.

Therefore, $1$ mole of $H_2{O}_2$ will give $11.2$ L of $O_2$ gas.

So, volume strength of $H_2{O}_2=11.2\times$ molarity.

Hence, for $1\text{M}$ $H_2{O}_2$, volume strength is $11.2$.