Question

$W_1$ g of an element combines with oxygen forming $W_2$ g of its oxide.The equivalent mass of the element is :

• A. $\left[\frac{W_1}{W_2}\right]\times 8$
• B. $[\frac{W_1}{W_2-W_1}]\times 8$
• C. $[\frac{W_2-W_1}{W_1}]\times 8$
• D. $[\frac{W_1}{W_1-W_2}]\times 8$

Answer 1

The correct option is B $[\frac{W_1}{W_2-W_1}]\times 8$

Mass of oxygen in its oxide $=W_2-W_1$
As $W_1$ mass of element combines with $=W_2-W_1$ g of oxygen,
Equivalent mass of element is $[\frac{W_1}{W_2-W_1}]\times 8$. (mass of an element that combines with 8 g of oxygen is its equivalent weight)