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Question

Walking at three-fourth of his usual speed, a man covers a certain distance in 2 hours more than the time he takes to cover the distance at his usual speed. What is the time taken by him cover the same distance with his usual speed?

A
4 hours
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B
9 hours
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C
2 hours
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D
6 hours
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Solution

The correct option is D 6 hours
We know that, V=DT.......(i), where V= usual speed, D= distance and T= usual time.
As given in question, V×34=DT+2.......(ii)
Solving (i) and (ii), we have
DT×34=DT+2
T=6 hours

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