Question

Watee is filled in a conical flask up to a height of 20cm. If the radius of the base is 14 cm, find the force exerted on the bottom of the flask.

Answer 1

Dear Student ,
Here in this question the height and radius of the 20 cm and 14 cm of a conical flask .
So the area of the base of the conical flask is , A = $\mathrm{\pi }{\left(14\right)}^2=615·75{\mathrm{cm}}^2$
Therefore , the volume of the water = $\frac{1}{3}\pi r^2\times h=\frac{1}{3}\times A\times L=\frac{1}{3}\times 615·75\times 20=4105c{m}^3$
Now we know that the density of water is $\rho =1g/cc$
So , the force exerted by the water at the bottom of the conical flask is ,
$$\begin{gathered} F=Mg=V\times \rho \times g \\ =4105\times 1\times 980 \\ =4·023\times {10}^{6}dyne \end{gathered}$$
Regards