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Question

# Water and chlorobenzene are immiscible liquids. Their mixture boils at 89oC under a reduced pressure of 7.7×104 Pa. The vapour pressure of pure water at 89oC is 7×104 Pa. Weight percent of chlorobenzene in the distillate is:

A
50
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B
60
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C
79
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D
38.46
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Solution

## The correct option is C 79Vapour pressure = 7.7×104 PaTotal pressure = 7×104 PaPartial pressure = Vapour pressure = Mole fraction x Total pressureMole fraction of H2O = VapourpressureTotalpressure = 7.7×1047×104 = 0.909Mole fraction of CHCl3 = 1 - 0.909 = 0.091Molar mass of H2O = 18g/molMolar mass of CHCl3 = 119.5g/molWeight percent of chloroform = Mole fraction of CHCl3 x Molar mass of CHCl3 / [Molar mass of CHCl3 +Molar mass of H2O }Weight percent of chloroform = 79%Answer is 79%.

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