Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v₁ and v₂ respectively.
(a) v₁ = v₂
(b) v₁ = 13.6 v₂
(c) v₁ = v₂/13.6
(d) $v_{1} = \sqrt{13.6} v_{2}$

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Solution

(a) v₁ = v₂

The velocity of efflux does not depend on the density of the liquid. It only depends on the height h (given same in the question) and acceleration due to gravity g (constant value here).

$v_{1} = v_{2} = v = \sqrt{2 g h}$

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Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are v1 and v2 respectively. (a) v1 = v2 (b) v1 = 13.6 v2 (c) v1 = v2/13.6 (d) v1=13.6 v2

(a) v1 = v2 The velocity of efflux does not depend on the density of the liquid. It only depends on the height h (given same in the question) and acceleration due to gravity g (constant value here). v1=v2=v=2gh

(a) v₁ = v₂

The velocity of efflux does not depend on the density of the liquid. It only depends on the height h (given same in the question) and acceleration due to gravity g (constant value here).

$v_{1} = v_{2} = v = \sqrt{2 g h}$