Water contained in a tank flows through a orifice of diameter $2 c m$ , under a constant pressure difference of $10 c m$ of water column. The rate of flow of water through the orifice

44 c c / s

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4.4 c c / s

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440 c c / s

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40 c c / s

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Solution

The correct option is C $440 c c / s$
$v = \sqrt{2 g h} = \sqrt{2 \times 9.8 \times 10 \times 10^{2}} = 1.4 m / s$
Radius of orifice $= 1 c m = 10^{- 2} m$
Rate of flow of liquid through orifice will be
$Q = v \times a r e a = 1.4 \times 3.14 \times 10^{- 4} Q = 4.40 \times 10^{- 4} Q = 440 c c / s e c$

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Water contained in a tank flows through a orifice of diameter 2cm, under a constant pressure difference of 10cm of water column. The rate of flow of water through the orifice

The correct option is C 440cc/s v=√2gh=√2×9.8×10×102=1.4m/sRadius of orifice=1cm=10−2mRate of flow of liquid through orifice will be Q=v×area=1.4×3.14×10−4Q=4.40×10−4Q=440cc/sec

Water contained in a tank flows through a orifice of diameter $2 c m$ , under a constant pressure difference of $10 c m$ of water column. The rate of flow of water through the orifice