Water does not produce $C O$ on reacting with:

C_{3} H_{8}

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C

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C H_{4}

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C O_{2}

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Solution

The correct option is D $C O_{2}$
(a) $C_{3} H_{8} + 3 H_{2} O 1270 K - --- \to N i 3 C O + 7 H_{2}$

(b) $C + H_{2} O 1270 K - --- \to C O + H_{2}$

(c) $C H_{4} + H_{2} O 1270 K - --- \to N i C O + 3 H_{2}$

(d) $H_{2} O + C O_{2} \to H_{2} C O_{3}$

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Similar questions

P_{4} O_{10}

on reacting with water does not form :

Barium reacts vigorously even with cold water while Mg reacts slowly with warm water. Mg does not react with cold water easily while Beryllium does not react even with boiling water.

Q. Metals generally react with dilute acids to produce hydrogen gas. Which one of the following metals does not react with dilute hydrochloric acid?

C O

does not react with water to form

H C O O H

. If true write 1, else write 0.

(a) Name one metal which reacts with dilute hydrochloric acid to produce hydrogen gas.

(b)Name one metal which does not react with dilute hydrochloric acid.

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Water does not produce CO on reacting with:

The correct option is D CO2(a) C3H8+3H2O1270K−−−−→Ni3CO+7H2 (b) C+H2O1270K−−−−→CO+H2 (c) CH4+H2O1270K−−−−→NiCO+3H2 (d)H2O+CO2→H2CO3

Water does not produce $C O$ on reacting with:

The correct option is D $C O_{2}$
(a) $C_{3} H_{8} + 3 H_{2} O 1270 K - --- \to N i 3 C O + 7 H_{2}$

(b) $C + H_{2} O 1270 K - --- \to C O + H_{2}$

(c) $C H_{4} + H_{2} O 1270 K - --- \to N i C O + 3 H_{2}$

(d) $H_{2} O + C O_{2} \to H_{2} C O_{3}$