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Question

Water falling from a 50 m high fall is to be used for generating electric energy. If 1.8×105kg of water falls per hour and half the gravitational potential energy can be converted into electric energy, how many 100 W lamps can be lit?

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Solution

h = 50m, m =1.8×105kghr, P = 100 watt,
P.E. = mgh = 1.8×105×9.8×50 = 882×105Jhr
Because, half the potential energy is converted into electricity,
Electrical energy 12×P.E. =441×105Jhr So, power in watt is given by = 441×1053600
∴ number of 100 W lamps, that can be lit 441×105360000 = 122.5 = 122

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