Question

Water falls from a height 500 m. What is the rise in temperature of water at bottom if whole energy remains in the water ? ($1J=4.2cal$)

• A. ${0.96}^{0}C$
• B. ${1.02}^{0}C$
• C. ${1.19}^{0}C$
• D. ${0.23}^{0}C$

Answer 1

Answer: (C)

${1.19}^{0}C$

Change in potential energy$=$Energy absorbed by the water
$mgh=mc\Delta T$
$\Delta T=\frac{\left(10\right)\left(500\right)}{4.2\times 1000}={1.19}^{o}C$