Water falls from a height of 50 cm. Calculate the rise in temperature of water when it strikes the bottom. ( $g = 10 m s^{- 2}$ , sp. heat capacity of water $= 4200 J / k g^{o} C$ )

Open in App

Solution

Let the rise in temperature be T $^{o}$ C. Then, Heat produced by water = Loss in potential energy
$\Rightarrow m s T = m g h \Rightarrow T = \frac{g h}{s} = \frac{10 \times 50}{4200} = \frac{5}{42} = {0.12}^{o} C$
The rise in temperature = ${0.12}^{o} C$

Suggest Corrections

Similar questions

Water falls from a height of 50 m. Calculate the rise in temperature of water when it strikes the bottom. Take g = 10 m s^-2 and specific heat capacity of water = 4200 J kg^-1 °C^-1).

Water falls from a height of 100 m. Calculate the rise in temperature of water when it strikes the bottom. Given, S $_{w}$ = 4200 Jkg $^{- 1}$ $^{0}$ C $^{- 1}$ and g = 10 m/s $^{2}$ .

Q. Water falls from a height of 100 m. Find the rise in temperature of the water when it reaches the bottom, assuming all its energy is converted to heat at the bottom of the waterfall.

(g = 10 m s^{- 2}, s_{w} = 4200 J k g^{- 1} K^{- 1})

1 k g

of water is supplied

630 k J

of energy. Specific heat of water is

4200 J / k g^{o} C

. Calculate the rise in temperature of

1 k g

water :

Q. The specific heat capacity of water is

4200 J / k g^{o} C

. Calculate the heat capacity of

10 k g

of water per

^{o} C

Join BYJU'S Learning Program

Water falls from a height of 50 cm. Calculate the rise in temperature of water when it strikes the bottom. (g=10ms−2, sp. heat capacity of water =4200J/kgoC)

Let the rise in temperature be ToC. Then, Heat produced by water = Loss in potential energy⇒msT=mgh⇒T=ghs=10×504200=542=0.12oCThe rise in temperature = 0.12oC

Water falls from a height of 50 cm. Calculate the rise in temperature of water when it strikes the bottom. ( $g = 10 m s^{- 2}$ , sp. heat capacity of water $= 4200 J / k g^{o} C$ )

Let the rise in temperature be T $^{o}$ C. Then, Heat produced by water = Loss in potential energy
$\Rightarrow m s T = m g h \Rightarrow T = \frac{g h}{s} = \frac{10 \times 50}{4200} = \frac{5}{42} = {0.12}^{o} C$
The rise in temperature = ${0.12}^{o} C$