Water flows between two plates, of which the upper one is stationary and the lower one is moving with a velocity $V$ . What will be the velocity of the fluid in contact with the upper plate?

V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{V}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $0$
Since the upper plate is stationary, according to the no-slip condition, the relative velocity between the plate and the fluid in contact with it must be zero.
Thus, the velocity of the fluid layer in contact with the upper plate is $0$ and of the fluid layer in contact with the lower plate will be $V$ .

Suggest Corrections

Similar questions

Q. Water flows between two plates, of which the upper one is stationary and the lower one is moving with a velocity

V

. What will be the velocity of the fluid in contact with the upper plate?

Q. The space between two plates

20 cm \times 20 cm \times 1 cm, 1 cm

apart is filled with a liquid of viscosity

1 Poise

. The upper plate is dragged to the right with a force of

F = 5 N

keeping the lower plate stationary. The upper plate is moving at a constant speed

u

as shown in figure.

What will be the velocity in

m/s

of the flow at a point

0.5 cm

below the lower surface of the upper plate if linear velocity profile is assumed for the flow ?

Q. A plate is moving with velocity

5 m/s

parallel to a plate that is held stationary at a distance of

10 mm

below the upper plate. If the space between the plates is filled with water having coefficient of viscosity

9 \times 10^{- 4}

s

, then the shear stress acting on the surface of the moving plate assuming linear velocity profile between plates will be

Two immiscible, incompressible, viscous fluids having same densities but different viscosities are contained between two infinite horizontal parallel plates, 2 m apart as shown below. The bottom plate is fixed and the upper plate moves to the right with a constant velocity of 3 m/s. With the assumptions of Newtonian fluid, steady and fully developed laminar flow with zero pressure gradient in all directions, the momentum equations simplify to

$\frac{d^{2} u}{d y^{2}} = 0$

If the dynamic viscosity of the lower fluid $μ_{2}$ , is twice that of the upper fluid $μ_{1},$ then the velocity at the interface (round off to two decimal places) is m/s.