Water flows in a horizontal tube as shown in figure. The pressure of water changes by 600 N/m2 between x and y where the areas of cross section are 3 cm2 and 1.5 cm2 respectively. Find the rate of flow of water through the tube.
189 cm3/s
By equation of continuity
VyVx=3 cm21.5 cm2=2
By Bernoulli’s equation
Px+12ρv2x=Py+12ρv2y
Px−Py=31ρv2x
vx=0.63 m/s
Q=Ax vx=(3 cm2)(0.63 m/s)=189 cm3/s