Question

# Water flows in a horizontal tube as shown in figure. The pressure of water changes by 600 N/m2 between x and y where the areas of cross section are 3 cm2 and 1.5 cm2 respectively. Find the rate of flow of water through the tube.   189 cm3/s 199 cm3/s 169 cm3/s 179 cm3/s

Solution

## The correct option is A 189 cm3/s By equation of continuity VyVx=3 cm21.5 cm2=2 By Bernoulli’s equation Px+12ρv2x=Py+12ρv2y Px−Py=31ρv2x vx=0.63 m/s Q=Ax vx=(3 cm2)(0.63 m/s)=189 cm3/s

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