Question

Water flows in an inclined pipe at an angle ${30}^o$ from horizontal as shown. The pressure at section (1) is 20 $kN/m^2$ and at section (2) is 10 $kN/m^2$. If the head loss between the sections is 0.6 m of water, then the distance between the two sections is :

• A. 0.42 m
• B. 0.66 m
• C. 0.84 m
• D. 1.12 m

Answer 1

The correct option is C 0.84 m


Applying Bernoulli's equation between section (1) and (2) ;

$\frac{P_1}{\gamma }+\frac{V_1^2}{2g}+z_1=\frac{P_2}{\gamma }+\frac{V_2^2}{2g}+z_2+H_L$

$\frac{20}{9.81}+\frac{V^2}{2g}+0=\frac{10}{9.81}+\frac{V^2}{2g}+L\sin {30}^o+0.6$

Due to Velocity being same at both sections ,

$V_1=V_2=V$

$\frac{10}{9.81}-0.6=L\sin {30}^o$

L = 0.838 m