Water flows out of pipe whose cross section is a rectangle 20 cm x 10 cm at a rate of 50 m/second. The area irrigated in 4 hours if 4.8 cm of standing water is required is

0.5 ha

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1000

m^{2}

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10 ha

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30 ha

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Solution

The correct option is D 30 ha
$(\frac{2}{10} \times \frac{1}{10}) \times 50 \times 3600 \times 4 = \frac{4.8}{100} \times$ Area irrigated
$∴ A r e a = 30000 m^{2} = 30 h a$

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Water flows out of pipe whose cross section is a rectangle 20 cm x 10 cm at a rate of 50 m/second. The area irrigated in 4 hours if 4.8 cm of standing water is required is

The correct option is D 30 ha(210×110)×50×3600×4=4.8100×Area irrigated∴Area=30000m2=30ha

The correct option is D 30 ha
$(\frac{2}{10} \times \frac{1}{10}) \times 50 \times 3600 \times 4 = \frac{4.8}{100} \times$ Area irrigated
$∴ A r e a = 30000 m^{2} = 30 h a$