Question

Water flows out through a circular pipe whose internal diameter is 2 cm, at the rate of 6 meters per seconds into a cylindrical tank. The radius of whose base is 60 cm. Find the rise in the level of water in 30 minutes ?

Answer 1

Internal diameter of the pipe = 2 cm

$\therefore Radius\left(r\right)=\frac{2}{2}=1$ cm

Speed of water flow = 6m per second

Water in 30 minutes (h) = 6 $\times 60\times$ 30 m

= 10800 m

$\therefore$ Volume of water = $\pi r^2$ h

=$\frac{22\times 10800}{100\times 100\times 7}{m}^3$

Now radius of the base of cylindrical tank

(R) = 60 cm

and let height of water = H, then

$\pi R^{2}H=\frac{22\times 108000}{7\times 100\times 100}$

$\Rightarrow \frac{22}{7}\times \frac{60}{100}\times \frac{60}{100}H=\frac{22\times 10800}{7\times 100\times 100}$

$\therefore H=\frac{22\times 10800\times 7\times 100\times 100}{7\times 22\times 60\times 60\times 100\times 100}$

=3 m