Question

Water flows out through a circular pipe whose internal diameter is 2cm ,at the rate of 6 metres per second into a cylindrical tank. The radius of whose base is 60cm. Find the rise in the level of water in 30minutes.

Answer 1

Vol of water delivered in 30minute (π r^2l)
= π×1×1 ×600×60×30 cm3

{ since radius of pipe = 1cm, 6m = 600 cm,
30m = 30 ×60 = 1800 sec}

Area of cylindrical tank = π×60×60 cm2

Therefore, the rise in the level will be = Vol.of water delivered in 30minute / Area of cylindrical tank

= (π× 1×1 ×600×60×30 cm3)/ π×60×60 cm2

= 300cm = 3metres

Thus, the rise in level of water in the cylindrical tank = 3metres