wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

)Water flows out through a circular pipe whose internal diameter is 2cm,at the rate of 6 meters per second into a cylindrical tank,the radius of whole base is 60 cm.By how much will the level of water rise in 30 minutes

Open in App
Solution

Dear student
Internal diameter of the pipe=2cmInternal radius of pipe=1cmRate of water flow=6m/sec=600cm/secTherefore, Volume of water which flows in 1sec=Base area of the pipe×Rate of water flow=227×1×1×600 cm3=22×6007cm3Therefore, Volume of water which flows in 30 min=22×6007×30×60 cm3 As 30min=30×60secIt is collected in the cylindrical tank of base radius 60cm.Let risein water level be h cm.Volume of watre added in it=Volume of water which flows in 30 minπr2h=22×6007×30×60227×60×60×h=22×6007×30×60h=300cmh=3m
Regards

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basics
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon