Question

Water flows out through circular pipe whose external diameter is $2cm$ at a rate of $0.7m/s$ into cylindrical tank whose radius is $40cm$, by how much will water level rise in half an hour.

Answer 1

$Volumeofwaterflowingpersecond=0.7\times \pi \times (\frac{1}{100}{)}^2{m}^3=22\times {10}^{-5}{m}^{3}Volumetransferredinhalfanhour=22\times {10}^{-5}\times 1800m^3=396\times {10}^{-3}{m}^{3}letheightuptowhichwaterrisesbehthenh\times \pi \times (\frac{40}{100}{)}^2=396\times {10}^{-3}\therefore h=0.7875m=78.75cm\approx 79cm$