Water flows through a 60 cm diameter, 1 km long pipe from a 30 m head of over tank to a village. Ignore minor losses. Fanning friction factor =0.04. The discharge (cumec) at the village ground level is

1.68 m^{3} / s e c

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0.75 m^{3} / s e c

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0.84 m^{3} / s e c

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0.94 m^{3} / s e c

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Solution

The correct option is C $0.84 m^{3} / s e c$
$h_{f} = \frac{f . L . Q^{2}}{12.1 (d)^{5}}$

$30 = \frac{0.04 \times 1000 \times Q^{2}}{12.1 \times (0.6)^{5}}$

$Q = 0.84 m^{3} / s e c$

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A pipe of 0.7 m diameter has a length of 6 km and connects two reservoirs A and B. The water level in reservoir A is at an elevation 30 m above the water level in reservoir B. Halfway along the pipe line, there is a branch through which water can be supplied to a third reservoir C. The friction factor of the pipe is 0.024. the quantity of water discharged into reservoir C is 0.15 m $^{3}$ /s. Considering the acceleration due to gravity as 9.81 m/s $^{2}$ and neglecting minor losses, the discharge (in m $^{3}$ /s) into the reservoir B is

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Water flows through a 60 cm diameter, 1 km long pipe from a 30 m head of over tank to a village. Ignore minor losses. Fanning friction factor =0.04. The discharge (cumec) at the village ground level is

The correct option is C 0.84m3/sechf=f.L.Q212.1(d)5 30=0.04×1000×Q212.1×(0.6)5 Q=0.84m3/sec

The correct option is C $0.84 m^{3} / s e c$
$h_{f} = \frac{f . L . Q^{2}}{12.1 (d)^{5}}$

$30 = \frac{0.04 \times 1000 \times Q^{2}}{12.1 \times (0.6)^{5}}$

$Q = 0.84 m^{3} / s e c$