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Question

Water from a tap emerges vertically downwards with an initial velocity V0.assuming pressure is constant throughout the stream of water and the flow is steady, find the distance from the tap at which cross-sectional area of stream is half of the cross-sectional area of stream at the tap:

A
V20/2g
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B
3V20/2g
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C
2V20/g
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D
5V20/2g
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Solution

The correct option is C 3V20/2g

Applying equation of Continuity A,V1=A2V2AV0=A2V[V=2V0]

Applying Bernoul's Theorn

12ρv2+fgh1+Pk= constant 12gv21+ρgh1+p1=12ρv22+ρgh2+P2
12ρ(v21v22)+1g(h1h2)+(p1/p2)=012ρ(3v20)+ρgh=0h=3v202g

Hence option B is correct

1991253_985612_ans_f8c0985b47fc4bc09364178be4475381.PNG

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