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Fluid Mechanics

Reynold's Model Law

Water having ...

Question

Water having kinematic viscosity of 0.01 stokes flows at a velocity of 2 m/sec in a pipe of 15 cm diameter. For dynamic similarity, the velocity of oil of kinematic viscosity 0.03 stoke in a pipe of same diameter will be

0.33 m/sec

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0.66 m/sec

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2 m/sec

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6 m/sec

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Solution

The correct option is D 6 m/sec
For dynamic similarity. Reynolds model law will be used.
$R e = \frac{V_{1} D}{ν_{1}} = \frac{V_{2} D}{ν_{2}} V_{2} = 2 \times \frac{0.003}{0.001} = 6 m / s$

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Water having kinematic viscosity of 0.01 stokes flows at a velocity of 2 m/sec in a pipe of 15 cm diameter. For dynamic similarity, the velocity of oil of kinematic viscosity 0.03 stoke in a pipe of same diameter will be

The correct option is D 6 m/secFor dynamic similarity. Reynolds model law will be used. Re=V1Dν1=V2Dν2V2=2×0.0030.001=6 m/s

The correct option is D 6 m/sec
For dynamic similarity. Reynolds model law will be used.
$R e = \frac{V_{1} D}{ν_{1}} = \frac{V_{2} D}{ν_{2}} V_{2} = 2 \times \frac{0.003}{0.001} = 6 m / s$