Question

Water in a bucket is whirled in a vertical circle with a string attached to it. The water does not fall down even when the bucket is inverted at the top of its path. We conclude that in this position.

• A. mg = $\frac{m{v}^2}{r}$
• B. mg is greater than $\frac{m{v}^2}{r}$
• C. mg is not greater than $\frac{m{v}^2}{r}$
• D. mg is not less than $\frac{m{v}^2}{r}$

Answer 1

The correct option is C

mg is not greater than $\frac{m{v}^2}{r}$

At topmost point draw free body diagram of water in the bucket and see.

Since its going in a circle, so a centripetal acceleration on it.

mg + N = $\frac{m{v}^2}{R}$

mg = $\frac{m{v}^2}{R}-N$

Now N $\ge$ 0