Water in a bucket is whirled in a vertical circle with a string attached to it. The water does not fall down even when the bucket is inverted at the top of its path. We conclude that in this position.

mg =

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mg is greater than

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mg is not greater than

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mg is not less than

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Solution

The correct option is C
mg is not greater than

At topmost point draw free body diagram of water in the bucket and see.

Since its going in a circle, so a centripetal acceleration on it.

mg + N = $\frac{m v^{2}}{R}$

mg = $\frac{m v^{2}}{R} - N$

Now N $\geq$ 0

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Similar questions

Q. Water in a bucket is whirled in a vertical circle with string attached to it. The water does no fall down even when the bucket is inverted at the top of its path. We conclude that in this position
(a)

m g = \frac{m v^{2}}{r}

(b) mg is greater than

\frac{m v^{2}}{r}

\frac{m v^{2}}{r}

(d) mg is not less than

\frac{m v^{2}}{r}

Water in a bucket is whirled in a vertical circle with a string attached to it. The water does not fall down even when the bucket is inverted at the top of its path. We conclude that in this position.

Q. Water in a bucket is whirled in a vertical circle with a string to it. The water does not fallen even when the bucket is inverted at the top of its path . We conclude that in this position:

Q. A bucket is whirled in a vertical circle with a string attached to it. The water in the bucket does not fall down even when the bucket is inverted at the top of its path. We can say that in this position.

Q. A bucket is whirled in a vertical circle with a string attached to it.The water in bucket does not fall down even when the bucket is inverted at the top of its path. In this position choose most appropiate option.

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Water in a bucket is whirled in a vertical circle with a string attached to it. The water does not fall down even when the bucket is inverted at the top of its path. We conclude that in this position.

The correct option is C mg is not greater than At topmost point draw free body diagram of water in the bucket and see. Since its going in a circle, so a centripetal acceleration on it. mg + N = mv2R mg = mv2R−N Now N ≥ 0

The correct option is C
mg is not greater than

At topmost point draw free body diagram of water in the bucket and see.

Since its going in a circle, so a centripetal acceleration on it.

mg + N = $\frac{m v^{2}}{R}$

mg = $\frac{m v^{2}}{R} - N$

Now N $\geq$ 0