Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

Open in App

Solution

Depth = 1.5 m, width = 6 m, height of standing water = 0.08 m
In 30 minutes, length of water column = 5 km = 5000 m
Volume of water in 30 minutes $= 1.5 \times 6 \times 5000 = 45000 m^{3}$
$A r e a = \frac{V o l u m e}{H e i g h t}$
$= \frac{45000}{0.08} = 562500 m^{2}$

Suggest Corrections

Similar questions

Q. Water in canal,

6

m wide and

1.5

m deep, is flowing with a speed of

10

km/h. How much area will it irrigate in

30

minutes, if

8

cm of standing water is needed?

Q. Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/hr. How 3 much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate (in $m^{2}$ ) in 30 minutes, if 8 cm of standing water is needed?

Water in canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. how much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

Q. Water in a canal,

6 m

wide and

1.5 m

deep, is flowing with a speed of

10 k m / h

. How much area will it irrigate in

30

minutes, if

8 c m

of standing water is needed?

Join BYJU'S Learning Program

Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

Depth = 1.5 m, width = 6 m, height of standing water = 0.08 m In 30 minutes, length of water column = 5 km = 5000 m Volume of water in 30 minutes =1.5×6×5000=45000 m3 Area = VolumeHeight =450000.08=562500 m2

Depth = 1.5 m, width = 6 m, height of standing water = 0.08 m
In 30 minutes, length of water column = 5 km = 5000 m
Volume of water in 30 minutes $= 1.5 \times 6 \times 5000 = 45000 m^{3}$
$A r e a = \frac{V o l u m e}{H e i g h t}$
$= \frac{45000}{0.08} = 562500 m^{2}$