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Standard VII

Physics

Sea Breeze and Land Breeze

Water in a la...

Question

Water in a lake is converted into ice at $0^{o} C$ whereas atmospheric temperature is $- 10^{o} C$ . How many hours are taken in freezing $1 c m$ thick ice layer:

7 h o u r s

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14 h o u r s

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less than

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Solution

The correct option is A $7 h o u r s$
$t = \frac{ρ L}{2 K θ} x^{2} - θ = - 10 ° C ∴ θ = 263 K$

K of ice $= 2.184 W / m / k$

$ρ$ of ice $= 920 k g m^{- 3}$

L $= 333 k J / k g$

$x = 0.01 m$

$∴ t = \frac{920 \times 333}{2 \times 2.184 \times 263} \times {(0.01)}^{2} \approx 7 h o u r s$

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Water in a lake is converted into ice at 0oC whereas atmospheric temperature is −10oC. How many hours are taken in freezing 1 cm thick ice layer:

The correct option is A 7 hourst=ρL2Kθx2−θ=−10°C∴θ=263K K of ice =2.184W/m/k ρ of ice =920kgm−3 L =333kJ/kg x=0.01m ∴t=920×3332×2.184×263×(0.01)2≈7hours

Water in a lake is converted into ice at $0^{o} C$ whereas atmospheric temperature is $- 10^{o} C$ . How many hours are taken in freezing $1 c m$ thick ice layer:

The correct option is A $7 h o u r s$
$t = \frac{ρ L}{2 K θ} x^{2} - θ = - 10 ° C ∴ θ = 263 K$

K of ice $= 2.184 W / m / k$

$ρ$ of ice $= 920 k g m^{- 3}$

L $= 333 k J / k g$

$x = 0.01 m$

$∴ t = \frac{920 \times 333}{2 \times 2.184 \times 263} \times {(0.01)}^{2} \approx 7 h o u r s$