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Question

Water is added in excess to a 100 g sample labelled as 112% H2SO4 This solution is then treated with 5.3 g of Na2CO3. the volume of CO2 evolved at 1atm and 300 K after a complete reaction will be :
H2SO4+Na2CO3Na2SO4+H2O+CO2

A
2.46 L
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B
24.60 L
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C
1.27 L
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D
12.30 L
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Solution

The correct option is C 1.27 L
112% H2SO4 means water is in excess and the mass of H2SO4 112 g
Reaction :
H2SO4+Na2CO3NaSO4+CO2+H2O
number of mole of H2SO4=112/98
number of mole of Na2CO3=5.3/106=0.05
Na2CO3 is limiting reagent so 0.05 moles of CO2 produced at STP which volume is eqaul to 1.27 L

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