Question

Water is filled in a container upto height of $3m$. A small hole of area '$A_0$' is punched in the wall of the container at a height $52.5cm$ from the bottom. The cross sectional area of the container is A. If $A_0/A=0.1$ then $v^2$ is (where $v$ is the velocity of water coming out of the hole)

• A. $50m^2/s^2$
• B. $50.5m^2/s^2$
• C. $51m^2/s^2$
• D. $52m^2/s^2$

Answer 1

The correct option is A $50m^2/s^2$

The square of the velocity of flux

$v^2=\frac{2gh}{1-(\frac{A_o}{A}{)}^2}$

$=\frac{2\times 10\times 2.475}{1-(0.1{)}^2}=50m^2/s^2$