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Question

Water is filled in a rectangular tank of size 3 m × 2 m × 1 m. (a) Find the total force exerted by the water on the bottom surface on the tank. (b) Consider a vertical side of area 2 m × 1 m. Take a horizontal strip of width δx metre in this side, situated at a depth of x metre from the surface of water. Find the force by the water on this strip. (c) Find the torque of the force calculate in part (b) about the bottom edge of this side.
(d) Find the total force by the water on this side.
(e) Find the total torque by the water on the side about the bottom edge. Neglect the atmospheric pressure and take g = 10 ms−2.

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Solution

Dimensions of the rectangular tank:
Length, l = 3 m
Breadth, b = 2 m
Height, h = 1 m
Area of the bottom surface of the tank, A = 2×3=6 m2
Density of water, ρw = 1000 kgm−3

(a) Total force exerted by water on the bottom surface of the tank:
f=Ahρwg =6×1×103×10 =6×104=60,000 N

(b) Force exerted by water on the strip of width δx:
df=p×A=xρwg×A =x×103×10×2×δx =20,000xδx N

(c) Inside the tank, the water force acts in every direction due to adhesion. Therefore, torque is given by
di=F×r=20,000×δx(1-x) N

(d) Total force exerted by water on the side about the bottom edge F:
F=0120,000 xδx F=20,000x2201 =10,000 N
(e) Torque by the water on the side τ:
τ=20,000×01xδx1-x=20,000x22-x3301=20,000×12-13=20,0006 Nm =100003 Nm

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