Water is filled upto same height in two identical closed containers $A$ and $B$ . Container $A$ has vacuum over the water while container $B$ has air over the water. At the same depth of both the containers there is an opening on which identical balloons $A$ and $B$ are attached as shown in the figure given below. Then

Balloon -

A

will bulge more than balloon -

B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Balloon -

B

will bulge more than balloon -

A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both the balloons will bulge equally

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the balloons will bulge

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Balloon - $A$ will bulge more than balloon - $B$
Solution:- (A) Balloon $A$ will bulge more than balloon $B$ .
Since the container $A$ has vacuum over the water, thus water will cover the vacuum area first and hence the balloon $A$ will bulge more than balloon $B$ .

Suggest Corrections

Similar questions

Q. Water is filled up to the same height in two identical closed containers A and B. Container A has vacuum over the water while container B has aired over the water. At the same depth of both the containers, there is an opening on which identical balloons A and B are attached as shown in the figure given below. Then

Case 1: A balloon is fitted at the bottom of a cylinder which is half filled with water.
Case 2: A balloon is fitted at the bottom of a cylinder which is fully filled with water.
In which case will the balloon bulge more?

C a s e 1

: A balloon is fitted to the valve at the bottom of a cylinder which is half filled with water.

C a s e 2

: A balloon is fitted to the valve at the bottom of a cylinder which is fully filled with water.

Both the cylinder and valves are identical. In which case will the balloon bulge more out when the valves are opened?

The diagram below shows two identical glass tubes A and B tied with balloons at one end. Water is poured in tube A whereas kerosene is added in tube B. It is observed that bigger bulge is produced in tube A. Which of the following could explain this fact?

Q. Mohan has two identical balloons , one is white and one is black. Both are filled with the same amount of air and are tied so that no air can get in our out. What will happen if both balloons are put in or out. What will happen if both balloons are put in direct sunlight ?
A. The balloon will become larger than the white balloon.
B. The white balloon will become larger than black balloon.
C. Both balloon will stay the same size.
Write the number of correct alternative in the answer sheet.

Join BYJU'S Learning Program

The correct option is A Balloon - A will bulge more than balloon - BSolution:- (A) Balloon A will bulge more than balloon B. Since the container A has vacuum over the water, thus water will cover the vacuum area first and hence the balloon A will bulge more than balloon B.

The correct option is A Balloon - $A$ will bulge more than balloon - $B$
Solution:- (A) Balloon $A$ will bulge more than balloon $B$ .
Since the container $A$ has vacuum over the water, thus water will cover the vacuum area first and hence the balloon $A$ will bulge more than balloon $B$ .