Water is flowing at the rate of 15 kmph through a pipe of diameter 14 cm into a cuboid pond which is 50 m long and 44 m wide. In what time will the level of water in the pond rise by 21 cm ?
Water is flowing at the rate of 15 kmph through a pipe of diameter 14 cm into a cuboid pond which is 50 m long and 44 m wide. In what time will the level of water in the pond rise by 21 cm ?
Let the level of water in the pond rises by 21 cm in t hours.
Speed of water = 15 km/hr
Diameter of the pipe =14 cm= 14/100 m
Radius of the pipe (r) = 7/100 m
Volume of water flowing out of the pipe in 1 hour
= π r 2 h
= (22/7) x (7/100) x (7/100) x 15000
= 231 m3
Volume of water flowing out of the pipe in t hours = 231 t m3.
Volume of water in the cuboidal pond = lenght x wide x height
= 50 x 44 x (21/100) [ height = 21 cm =21/100 m]
= 462 m3
Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond
So, 231 t = 462
t = 2
Thus, the required time is 2 hours.
Let the level of water in the pond rises by 21 cm in t hours.
Speed of water = 15 km/hr
Diameter of the pipe =14 cm= 14/100 m
Radius of the pipe (r) = 7/100 m
Volume of water flowing out of the pipe in 1 hour
= π r 2 h
= (22/7) x (7/100) x (7/100) x 15000
= 231 m3
Volume of water flowing out of the pipe in t hours = 231 t m3.
Volume of water in the cuboidal pond = lenght x wide x height
= 50 x 44 x (21/100) [ height = 21 cm =21/100 m]
= 462 m3
Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond
So, 231 t = 462
t = 2
Thus, the required time is 2 hours.
