Question

Water is flowing at the rate of $2.53km/h$ through a cylindrical pipe into a cylindrical tank, the radius of the base is $40cm$. If the increase in the level of water in the tank, in half an hour is $3.15m$, find the internal diameter of the pipe.

Answer 1

Total inflow into the tank=total outflow

$2.53\times {10}^3\times 0.5\times \pi \times r^2=\pi \times {0.4}^2\times 3.15$

$r=2cm$

Hence diameter=$4cm$