Water is flowing at the rate of $500 {cm}^{3} / sec$ in a horizontal pipe of uniform cross-section area of $25 {cm}^{2}$ . The velocity of flow of water in $cm/s$ is

25 cm/sec

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15 cm/sec

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20 cm/sec

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50 cm/sec

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Solution

The correct option is C $20 cm/sec$
Given, rate of flow $(Q) = 500 {cm}^{3} / sec$
Area of cross-section of pipe $(A) = 25 {cm}^{2}$
Let the velocity of flow of water $= v$
We know,
$Q = A \times V$
$\Rightarrow 500 = 25 \times v$
$\Rightarrow v = 20 cm/sec$

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Equation of Continuity

Standard XII Physics

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Water is flowing at the rate of 500 cm3/sec in a horizontal pipe of uniform cross-section area of 25 cm2. The velocity of flow of water in cm/s is

The correct option is C 20 cm/secGiven, rate of flow (Q)=500 cm3/sec Area of cross-section of pipe (A)=25 cm2 Let the velocity of flow of water =v We know, Q=A×V ⇒500=25×v ⇒v=20 cm/sec

Water is flowing at the rate of $500 {cm}^{3} / sec$ in a horizontal pipe of uniform cross-section area of $25 {cm}^{2}$ . The velocity of flow of water in $cm/s$ is

The correct option is C $20 cm/sec$
Given, rate of flow $(Q) = 500 {cm}^{3} / sec$
Area of cross-section of pipe $(A) = 25 {cm}^{2}$
Let the velocity of flow of water $= v$
We know,
$Q = A \times V$
$\Rightarrow 500 = 25 \times v$
$\Rightarrow v = 20 cm/sec$