Water is flowing in a pipe of uniform cross section under constant pressure. At some place the pipe becomes narrow. The pressure of water at this place:

remains same

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may increase or decrease

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increases

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decreases

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Solution

The correct option is D decreases
Applying Bernoulli's $e q^{n}$
$\frac{P}{y} + \frac{v^{2}}{2 g} + z = c o n s t a n t$
$\frac{P_{A}}{y} + \frac{{V_{A}}^{2}}{2 g} + Z_{A} = \frac{P_{B}}{y} + \frac{{V_{B}}^{2}}{2 g} + Z_{B} - - (1)$
Assuming it a horizontal pipe,
now also applying equation of continuity
$A_{A} V_{A} = A_{B} V_{B}$
if $A_{A} > A_{B} \Rightarrow V_{A} < V_{B}$
if $V_{B} > V_{A}$ , then in eq(1)

$P_{A} > P_{B}$

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Similar questions

Water is flowing through a pipe under constant pressure. At some place the pipe becomes narrow. The pressure of water at this place:

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