Water is flowing steadily out through the end of a vertical pipe with a velocity of 4 ms-1. What will be the velocity of water at a distance from the end of the pipe where the area of cross section of the stream of water is (2/3)A? (Here A is the area of cross-section of the pipe)
6 ms-1
From the equation of continuity, we have
A1V1 = A2V2
Here, A1 = A and A2 = 2A/3
V1 = 4 ms-1
Hence,
A × 4 = (2A/3) × V2
V2 = 6 ms-1