wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Water is flowing steadily out through the end of a vertical pipe with a velocity of 4 ms-1. What will be the velocity of water at a distance from the end of the pipe where the area of cross section of the stream of water is (2/3)A? (Here A is the area of cross-section of the pipe)


A

8 ms-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

1 ms-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

0.4 ms-1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

6 ms-1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

6 ms-1


From the equation of continuity, we have

A1V1 = A2V2

Here, A1 = A and A2 = 2A/3

V1 = 4 ms-1

Hence,

A × 4 = (2A/3) × V2

V2 = 6 ms-1


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Living Things Breathe
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon