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Question

Water is flowing steadily out through the end of a vertical pipe with a velocity of 4 ms-1. What will be the velocity of water at a distance from the end of the pipe where the area of cross section of the stream of water is (2/3)A? (Here A is the area of cross-section of the pipe)


A

8 ms-1

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B

1 ms-1

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C

0.4 ms-1

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D

6 ms-1

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Solution

The correct option is D

6 ms-1


From the equation of continuity, we have

A1V1 = A2V2

Here, A1 = A and A2 = 2A/3

V1 = 4 ms-1

Hence,

A × 4 = (2A/3) × V2

V2 = 6 ms-1


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