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Question

Water is flowing through a capillary tube at the rate of 20×106m3s1 . If an identical tube is connected in series, the rate of flow of water in m3s1 is :

A
20×106
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B
40×106
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C
0
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D
10×106
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Solution

The correct option is C 10×106
In poiseuillis eqn we see that,
Qα1L
Q=KL
So,
If an identical tube is connected in series i.e.,
the length is double as the tubes are identical so, from the relation we see that Q will be halved
So, new Q after adding an identical tube=10×106m3/s

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