Water is flowing through a capillary tube at the rate of 20×10−6m3s−1 . If an identical tube is connected in series, the rate of flow of water in m3s−1 is :
A
20×10−6
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B
40×10−6
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C
0
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D
10×10−6
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Solution
The correct option is C10×10−6 In poiseuillis eqn we see that, Qα1L Q=KL So, If an identical tube is connected in series i.e., the length is double as the tubes are identical so, from the relation we see that Q will be halved So, new Q after adding an identical tube=10×10−6m3/s