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Question

# Water is flowing through a capillary tube at the rate of 20×10−6m3/s.. Another tube of the same radius and double the length is connected in series to the first tube. Now the rate of flow of water in m3/s is

A
10×106
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B
3.33×106
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C
6.67×106
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D
20×106
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Solution

## The correct option is A 6.67×10−6Given,Q1=20×10−6m3/sFrom Hagen-Poiseuille equation,Flow rate, Q=πPr48ηl. . . . . . .(1)where, l= length of capillary tubeP= pressurer= radius of capillary tubeFrom equation (1),Q∝1lQ2Q1=l1l2Q2=Q1l3lQ2=Q13=20×10−63=6.67×10−6m3/sThe correct option is C.

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