Question

Water is flowing through a cylindrical pipe of internal diameter 2 cm, into a cylindrical tank of base radius 40
cm at the rate of 0.7 m/sec. By how much will the water rise in the tank in half an hour?

Answer 1

Dear Student
For pipe, radius , r = 1cm
water flowing in 1 sec, h = 0.7m = 7cm
Cylindrical Tank, R = 40 cm,
rise in water level = H cm
Volume of water flowing in 1 sec = πr²h = π x 1 x 1 x 70 = 70π cm³
Volume of water flowing in 60 sec = 70π x 60 cm³
Volume of water flowing in 30 minutes = 70π x 60 x 30 cm³
Volume of water in Tank = πr²H = π x 40 x 40 x H cm³
Volume of water in Tank = Volume of water flowing in 30 minutes
π x 40 x 40 x H = 70π x 60 x 30
H = 78.75cm

Regards