Water is flowing through a tube of non-uniform cross section. If the radius of the tube at the entrance and the exit is in the ratio 3 :2, then ratio of velocity of water entering and leaving the tube is:

8:27

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 :9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1:1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

9:4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 4 :9

From the continuity eqn:
$A_{1} V_{1} = A_{2} V_{2}$
$π {(3)}^{2} . V_{1} = π {(2)}^{2} . V_{2}$
$\Rightarrow \frac{V_{1}}{V_{2}} = \frac{4}{9} \Rightarrow V_{1} : V_{2} = 4 : 9$

Suggest Corrections

Similar questions

Water is flowing through a tube of non-uniform cross-section. If the ratio of radius of the tube at the entrance and exit is 3 : 2, then the ratio of velocity of liquid entering and leaving the tube is:

Q. Water is flowing through a non uniform radius tube. If ratio of the radius of entry and exit end of the pipe is 3:2 then the ratio of velocities of entring and exit liquid is

Q. Water flows through a non uniform tube of area of cross section 25,15,35 cm2 ratio of velocities of water at the sections A B C is

Q. Water is flowing through a horizontal tube of non-uniform cross section. At a place the radius of the tube is

1.0

and the velocity of water is

2

. What will be the velocity of water, where the radius of the pipe is

2.0

Q. Water is flowing through a horizontal tube of non - uniform cross - section. At a place the radius of the tube is

1.0 cm

and the velocity of water is

2 m/s

. Then, what will be the velocity of water at a point where the radius of the pipe is

2.0 cm

Join BYJU'S Learning Program

Water is flowing through a tube of non-uniform cross section. If the radius of the tube at the entrance and the exit is in the ratio 3 :2, then ratio of velocity of water entering and leaving the tube is:

The correct option is B 4 :9 From the continuity eqn:A1V1=A2V2π(3)2.V1=π(2)2.V2⇒V1V2=49⇒V1:V2=4:9

The correct option is B 4 :9

From the continuity eqn:
$A_{1} V_{1} = A_{2} V_{2}$
$π {(3)}^{2} . V_{1} = π {(2)}^{2} . V_{2}$
$\Rightarrow \frac{V_{1}}{V_{2}} = \frac{4}{9} \Rightarrow V_{1} : V_{2} = 4 : 9$