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Question

Water is flowing through two horizontal pipes of different diameter which are connected together. The diameter of the two pipes are 3 cm and 6 cm respectively. If the speed of water in the narrower tube is 4 m/s. Then, the speed of water in the wider tube is :

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Solution

The correct option is **B** 1 m/s

Radius of tube 1=[Diameteroftube12]=[32]cm

Radius of tube 2=[Diameteroftube22]=[62]cm=8cm

According to the equation of continuity :-

A1V1=A2V2

or R21V1=R22V2

Where

R1= Radius of tube 1

R2= Radius of tube 2

V1= Speed of water in narrow tube

V2= Speed of water in in wider tube

⇒(32)2×4=(3)2×V2

⇒94×4=9×V2

⇒V2=1m/s

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