Water is moving with a speed of 5.18 ms $^{-} 1$ through a pipe with a cross-sectional area of 4.20 $c m^{2}$ . The water gradually descends 9.66 m as the pipe increase in area to 7.60 $c m^{2}$ . The speed of flow at the lower level is

3.0 ms^-1

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5.7 ms^-1

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3.82 ms^-1

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2.86 ms^-1

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Solution

The correct option is D
2.86 ms^-1

$a_{1} v_{1} = a_{2} v_{2}$

$\Rightarrow 4.20 \times 5.18 = 7.60 \times v_{2} \Rightarrow v_{2} = 2.86 m / s$

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Similar questions

Q. Water is moving with a speed of

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Water is moving with a speed of 5.18 ms $^{-} 1$ through a pipe with a cross-sectional area of 4.20 $c m^{2}$ . The water gradually descends 9.66 m as the pipe increase in area to 7.60 $c m^{2}$ . The speed of flow at the lower level is

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in one minute, if speed of water in pipe is

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Water is flowing steadily out through the end of a vertical pipe with a velocity of 4 ms^-1. What will be the velocity of water at a distance from the end of the pipe where the area of cross section of the stream of water is (2/3)A? (Here A is the area of cross-section of the pipe)

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Water is moving with a speed of 5.18 ms−1 through a pipe with a cross-sectional area of 4.20 cm2. The water gradually descends 9.66 m as the pipe increase in area to 7.60 cm2. The speed of flow at the lower level is

The correct option is D 2.86 ms-1 a1v1=a2v2 ⇒4.20×5.18=7.60×v2⇒v2=2.86m/s

Water is moving with a speed of 5.18 ms $^{-} 1$ through a pipe with a cross-sectional area of 4.20 $c m^{2}$ . The water gradually descends 9.66 m as the pipe increase in area to 7.60 $c m^{2}$ . The speed of flow at the lower level is

The correct option is D
2.86 ms^-1

$a_{1} v_{1} = a_{2} v_{2}$

$\Rightarrow 4.20 \times 5.18 = 7.60 \times v_{2} \Rightarrow v_{2} = 2.86 m / s$