Water is moving with a speed of $5.18 m s^{- 1}$ through a pipe with a cross-sectional area of $4.20 c m^{2}$ . The water gradually descends 9.66 m as the pipe increase in area to $7.60 c m^{2}$ . The speed of flow at the lower level is

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Solution

The correct option is D
$a_{1} v_{1} = a_{2} v_{2} \Rightarrow 4.20 \times 5.18 = 7.60 \times v_{2} \Rightarrow v_{2} = 2.86 m / s$

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Water is moving with a speed of 5.18ms−1 through a pipe with a cross-sectional area of 4.20cm2. The water gradually descends 9.66 m as the pipe increase in area to 7.60cm2. The speed of flow at the lower level is

The correct option is D a1v1=a2v2⇒4.20×5.18=7.60×v2⇒v2=2.86 m/s

Water is moving with a speed of $5.18 m s^{- 1}$ through a pipe with a cross-sectional area of $4.20 c m^{2}$ . The water gradually descends 9.66 m as the pipe increase in area to $7.60 c m^{2}$ . The speed of flow at the lower level is

The correct option is D
$a_{1} v_{1} = a_{2} v_{2} \Rightarrow 4.20 \times 5.18 = 7.60 \times v_{2} \Rightarrow v_{2} = 2.86 m / s$