Water is moving with a speed of $5.18 m s^{- 1}$ through a pipe with a cross-sectional area of $4.20 c m^{2}$ . The water level gradually descends $9.66 m$ as the pipe increase in area to $7.60 c m^{2}$ . The speed of flow at the lower level is :

3.0 m s^{- 1}

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5.7 m s^{- 1}

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3.82 m s^{- 1}

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2.86 m s^{- 1}

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Solution

The correct option is D $2.86 m s^{- 1}$
Answer is D.
According to the law of continuity, $a_{1} v_{1} = a_{2} v_{2} .$
Therefore, $4.20 \times 5.18 = 7.60 \times v_{2}, v_{2} = 2.86 m / s$ .
Hence, the speed of flow at the lower level is 2.86 m/s.

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Water is moving with a speed of 5.18 ms $^{-} 1$ through a pipe with a cross-sectional area of 4.20 $c m^{2}$ . The water gradually descends 9.66 m as the pipe increase in area to 7.60 $c m^{2}$ . The speed of flow at the lower level is

Q. Water is moving with a speed of

5.18 m s^{- 1}

through a pipe with a cross-section area of

4.20 c m^{2}

. The water gradually descends

9.66 m

as the cross-sectional area of pipe is increased to

7.60 c m^{2}

. The speed of the flow of water at lower level is

Q. How many litres of water flows out of a pipe having an area of cross section of 5 cm² in 1 minute, if the speed of water in the pipe is 30 cm/sec?

Q. Water flows through a horizontal pipe of varying cross-section at the rate of

0.5 m^{2} s^{- 1}

. The speed of the water at a point where the area of cross section is

0.05 m^{2}

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Water is moving with a speed of 5.18ms−1 through a pipe with a cross-sectional area of 4.20cm2. The water level gradually descends 9.66m as the pipe increase in area to 7.60cm2. The speed of flow at the lower level is :

The correct option is D 2.86ms−1Answer is D.According to the law of continuity, a1v1=a2v2.Therefore, 4.20×5.18=7.60×v2,v2=2.86m/s.Hence, the speed of flow at the lower level is 2.86 m/s.

Water is moving with a speed of $5.18 m s^{- 1}$ through a pipe with a cross-sectional area of $4.20 c m^{2}$ . The water level gradually descends $9.66 m$ as the pipe increase in area to $7.60 c m^{2}$ . The speed of flow at the lower level is :

The correct option is D $2.86 m s^{- 1}$
Answer is D.
According to the law of continuity, $a_{1} v_{1} = a_{2} v_{2} .$
Therefore, $4.20 \times 5.18 = 7.60 \times v_{2}, v_{2} = 2.86 m / s$ .
Hence, the speed of flow at the lower level is 2.86 m/s.