Water is pouring into a cuboidal reservoir at the rate of $60$ litres per minute. If the volume of reservoir is $108$ $m^{3}$ , find the number of hours it will take to fill the reservoir.

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Solution

The volume of the reservoir $= 108 m^{3} = 108 \times 1000 = 108000$ litres [ $∵ 1 m^{3} = 1000$ litres]
Rate of water flow $= 60$ litres per minutes
Time to fill reservoir $= \frac{volume of reservoir}{Rate of flow}$

$=$ $\frac{108000 litres}{60 litres per minutes}$

$= 1800$ minutes

No of hours $= \frac{1800}{60} = 30$ hours.

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Water is pouring into a cuboidal reservoir at the rate of 60 litres per minute. If the volume of reservoir is 108 m3, find the number of hours it will take to fill the reservoir.

The volume of the reservoir =108 m3=108×1000=108000 litres [∵1 m3=1000 litres]Rate of water flow =60 litres per minutesTime to fill reservoir =volume of reservoirRate of flow= 108000 litres60 litres per minutes=1800 minutesNo of hours =180060=30 hours.

Water is pouring into a cuboidal reservoir at the rate of $60$ litres per minute. If the volume of reservoir is $108$ $m^{3}$ , find the number of hours it will take to fill the reservoir.