Water is pumped from a depth of $10 m$ and delivered through a pipe of cross section $10^{- 2} m^{2}$ upto a height of $10$ m. If it is needed to deliver a volume $0.2 m^{3}$ per second, find the power required. [ Use $g = 10 m / s^{2}$ ]

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Solution

$P . E . = m g H$
$(H = 10 + 10 = 20 m)$
$m = ρ V$
$m = 1000 \times 0.2 = 200$
$P . E . = 200 \times 9.8 \times 20 = 39200 J o u l e$
$t = 1 s e c$
$P o w e r = \frac{39200}{1} = 39200 w a t t = 39.2 K W$

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Water is pumped from a depth of 10 m and delivered through a pipe of cross section 10−2m2 upto a height of 10 m. If it is needed to deliver a volume 0.2 m3 per second, find the power required. [ Use g=10 m/s2]

P.E.=mgH(H=10+10=20m)m=ρVm=1000×0.2=200P.E.=200×9.8×20=39200Joulet=1secPower=392001=39200watt=39.2KW

Water is pumped from a depth of $10 m$ and delivered through a pipe of cross section $10^{- 2} m^{2}$ upto a height of $10$ m. If it is needed to deliver a volume $0.2 m^{3}$ per second, find the power required. [ Use $g = 10 m / s^{2}$ ]

$P . E . = m g H$
$(H = 10 + 10 = 20 m)$
$m = ρ V$
$m = 1000 \times 0.2 = 200$
$P . E . = 200 \times 9.8 \times 20 = 39200 J o u l e$
$t = 1 s e c$
$P o w e r = \frac{39200}{1} = 39200 w a t t = 39.2 K W$