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Question

Water jet is coming out of a hose pipe of diameter 20 cm with speed 20 cm/sec. It strike a man inelastically. Find the force exerted by water jet on the person.

A
5.04 N
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B
1.26 N
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C
2.52 N
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D
9.4 N
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Solution

The correct option is B 1.26 N
F = density × area ×velocity2
Convert V to m/s:
20/100=0.2
=0.2m/s
Density of water =1000kgm3
Convert the diameter length to be in meters :
20/100=0.2
Area of the outlet :
3.142×(0.2/2)2=3.142×0.12=0.03142
Doing the substitution :
F=1000×0.03142×0.22=1.2568

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