Water pressure at the bottom of centre of the box is equal to (atmospheric pressure $= 10^{5} N / m^{2}$ , density of water $= 1000 k g / m^{3}, g = 10 m / s^{2}$ )

1.1 M P a

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0.11 M P a

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0.101 M P a

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0.011 M p a

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Solution

The correct option is B $0.11 M P a$
The pressure at the bottom will be equal to the sum of atmospheric pressure and the pressure due to the weight of liquid.
$P = P_{a} + ρ g h = 10^{5} + 1000 \times 10 \times 1$
$= (10^{5} + 10^{4}) N / m^{2} = 0.11 M P a$

Suggest Corrections

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )

Q. If pressure at half depth of a lake is equal to

\frac{2}{3} r d

pressure at the bottom of the lake, then what is the depth of the lake?
(Take atmospheric pressure as

10^{5} Pa

, density of water as

1000 {kg/m}^{3}

and

g = 10 {m/s}^{2}

)

If the atmospheric pressure is $10^{5} \frac{N}{m^{2}}$ and the density of water $10^{3} \frac{k g}{m^{3}}$ . What will be the depth below the surface of water if pressure is equal to thrice the atmospheric pressure?

Q. Calculate the pressure exerted by water at the depth of 10m . (g=10 m/s²) Density of water=1000kg/m^3.

Q. A hole is made at the bottom of the tank filled with water (density

1000 k g / m^{3}

), If the total pressure at the bottom ofthe tankis 3 atmosphere
( 1 atmosphere =

10^{5} N / m^{2}

), then the velocity of efflux is :

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Water pressure at the bottom of centre of the box is equal to (atmospheric pressure =105N/m2, density of water =1000kg/m3,g=10m/s2)

The correct option is B 0.11MPaThe pressure at the bottom will be equal to the sum of atmospheric pressure and the pressure due to the weight of liquid.P=Pa+ρgh=105+1000×10×1=(105+104)N/m2=0.11MPa

The maximum value of water pressure in the box in which water is filled upto a height of 4 m is equal to (atmospheric pressure =105 N/m2, density of water =1000 kg/m3, g=10 m/s2)

Water pressure at the bottom of centre of the box is equal to (atmospheric pressure $= 10^{5} N / m^{2}$ , density of water $= 1000 k g / m^{3}, g = 10 m / s^{2}$ )

The correct option is B $0.11 M P a$
The pressure at the bottom will be equal to the sum of atmospheric pressure and the pressure due to the weight of liquid.
$P = P_{a} + ρ g h = 10^{5} + 1000 \times 10 \times 1$
$= (10^{5} + 10^{4}) N / m^{2} = 0.11 M P a$

The maximum value of water pressure in the box in which water is filled upto a height of $4 m$ is equal to (atmospheric pressure $= 10^{5} N / m^{2},$ density of water $= 1000 k g / m^{3}$ , $g = 10 m / s^{2}$ )