Question

Water rises in a capillary tube upto a height of 4 cm. If capillary is inclined at an angle of ${30}^0$ with the vertical, then what will be the position of water in the tube?

Answer 1

If the capillary is inclined at an angle of $\beta$ with the vertical, then the position of water in the tube is

$l=\frac{h}{\cos \beta }$

Here $h=4cm;\beta ={30}^0\therefore \cos \beta =\cos {30}^0=\frac{\sqrt{3}}{2}$

$\therefore l=\frac{4cm}{\frac{\sqrt{3}}{2}}=\frac{8}{1.732}cm$

$=4.6189$

or $l=4.62$