Question

Water rises in a capillary tube upto a height of $50\text{cm}$. The length of the water column when the capillary tube is tilted at an angle of ${45}^{\circ }$ is

• A. $\frac{50}{\sqrt{2}}\text{cm}$
• B. $50\sqrt{2}\text{cm}$
• C. zero
• D. None of these

Answer 1

The correct option is B $50\sqrt{2}\text{cm}$


$h=50\text{cm}$
$\alpha ={45}^{\circ }$
Since the height of vertical column remains same,
So, $L=\frac{h}{\sin \alpha }=\frac{50}{\sin {45}^{\circ }}$
$\Rightarrow L=50\sqrt{2}\text{cm}$